Jump Drive 13
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I've figured out how to play this single-handed solitaire: Play normally but track the turns and score each turn, and see how many turns it takes to get to 50.
For this play it took me 9 turns.
Turn | Score |
---|---|
1 | 1 |
2 | 2 |
3 | 3 |
4 | 5 |
5 | 8 |
6 | 13 |
7 | 26 |
8 | 49 |
9 | 86 |
It's interesting that the score starts as a Fibonacci sequence. This is from adding 1 card per turn with 1 VP on each of the cards.
I wonder if there is a sort of generalized fibonacci process where the numbers
In any case, I have a score to beat, winning in 8 turns instead of 9.